What is the domain of g(x)=(x+8)/(x^2-16+64) ?

The domain of g(x)=(x+8)/(x^2-16+64) is -infinity <x<infinity

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domain of g(x)=(x+8)/(x^2-16+64)

domain

g (x) = \frac{x + 8}{x ^{2} - 16 + 64}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x}{x ^{2} - x - 6}

f (x) = 120 x^{3} ln (\frac{x}{2})

f (x) = 2 x + 9 x^{- 1}

f (x) = \frac{1}{ln ( x ) - 1}

f (x) = x^{4} - 4 x^{2} + 2

What is the domain of g(x)=(x+8)/(x^2-16+64) ?
The domain of g(x)=(x+8)/(x^2-16+64) is -infinity <x<infinity