What is the domain of f(x)=ln(x^2+64) ?

The domain of f(x)=ln(x^2+64) is -infinity <x<infinity

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domain of f(x)=ln(x^2+64)

domain

f (x) = ln (x^{2} + 64)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{3 x}{8 x - 1}

y = \frac{7}{x ( x - 4 )}

y = \frac{6 x - 2 - 3}{x ^{2} + 1}

ln (4 - 3 x - x^{2})

f (x) = \frac{x}{( x ^{2} - 4 )}

What is the domain of f(x)=ln(x^2+64) ?
The domain of f(x)=ln(x^2+64) is -infinity <x<infinity