What is the domain of f(x)=(sin(x))/(2x^2-3x+1) ?

The domain of f(x)=(sin(x))/(2x^2-3x+1) is x 1

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domain of f(x)=(sin(x))/(2x^2-3x+1)

domain

f (x) = \frac{sin ( x )}{2 x ^{2} - 3 x + 1}

x < \frac{1}{2} or \frac{1}{2} < x < 1 or x > 1

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = \frac{1}{2}

The function domain

x < \frac{1}{2} or \frac{1}{2} < x < 1 or x > 1

5 + ln (x)

f (x) = (4 - 2)

f (x) = - x^{2} + 3 x + 2

f (x) = - x^{2} + 3 x + 1

\frac{1}{e ^{x} + 2}

What is the domain of f(x)=(sin(x))/(2x^2-3x+1) ?
The domain of f(x)=(sin(x))/(2x^2-3x+1) is x< 1/2 \lor 1/2 <x<1\lor x>1