What is the domain of y= 1/(sqrt(x-2)) ?

The domain of y= 1/(sqrt(x-2)) is x>2

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domain of y= 1/(sqrt(x-2))

domain

y = \frac{1}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = x^{2} y^{2} - 5 y^{2} x - 6 y^{2} - 14 + 2 x = 0

x y - 2 x - 3 y = 2

f (x) = \frac{sin ( x )}{2 + cos ( x )}

(x^{2} + 5 x - 5)^{3}

f (x) = - 0.6 x + 200