What is the domain of f(x)=(\sqrt[4]{3x+6})/(x-7) ?

The domain of f(x)=(\sqrt[4]{3x+6})/(x-7) is -2 7

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domain of f(x)=(\sqrt[4]{3x+6})/(x-7)

domain

- 2 \leq x < 7 or x > 7

Interval Notation

[- 2, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 2 \leq x < 7 or x > 7

f (x) = \frac{x + 6}{x ^{2} - 64}

f (x) = \frac{3 x - 9}{x ^{2} - 6 x - 7}

f (x) = lo g_{2} (8 - \frac{7 - 2 x}{3})

\frac{x - 2}{2 x + 5}

g (t) = 1 - 2^{t}

What is the domain of f(x)=(\sqrt[4]{3x+6})/(x-7) ?
The domain of f(x)=(\sqrt[4]{3x+6})/(x-7) is -2<= x<7\lor x>7