What is the domain of f(x)=sqrt((2x+9)/(x-1)) ?

The domain of f(x)=sqrt((2x+9)/(x-1)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((2x+9)/(x-1))

domain

f (x) = \frac{2 x + 9}{x - 1}

x \leq - \frac{9}{2} or x > 1

Interval Notation

(- \infty, - \frac{9}{2}] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{9}{2} or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - \frac{9}{2} or x > 1

f (x) = tan (5 x)

f (x) = - 2 x - 9

f (x) = - 2 x - 8

f (x) = \frac{- 2 x + 5}{- 3 x + 1}

f (x) = 8 x - 1 + 5 x^{2}

What is the domain of f(x)=sqrt((2x+9)/(x-1)) ?
The domain of f(x)=sqrt((2x+9)/(x-1)) is x<=-9/2 \lor x>1