What is the domain of f(x)= 1/(sqrt(x+10)) ?

The domain of f(x)= 1/(sqrt(x+10)) is x>-10

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domain of f(x)= 1/(sqrt(x+10))

domain

f (x) = \frac{1}{x + 10}

x > - 10

Interval Notation

(- 10, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 10

Find undefined (singularity) points:

x = - 10

Combine real regions and undefined points for final function domain

x > - 10

y = \frac{x}{x - 1}

f (x) = - 2 x (x - 1) (x - 8)

f (x) = x^{2} + 8 x + 3

f (x) = - 2 x (x - 1) (x - 6)

\frac{x + 1}{4 x ^{2} - 12 x + 9}

What is the domain of f(x)= 1/(sqrt(x+10)) ?
The domain of f(x)= 1/(sqrt(x+10)) is x>-10