What is the domain of f(x)=(sqrt(x-7))/(sqrt(x-7)-3) ?

The domain of f(x)=(sqrt(x-7))/(sqrt(x-7)-3) is 7 16

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domain of f(x)=(sqrt(x-7))/(sqrt(x-7)-3)

domain

f (x) = \frac{x - 7}{x - 7 - 3}

7 \leq x < 16 or x > 16

Solution steps

Find non-negative values for radicals:

x \geq 7

Find undefined (singularity) points:

x = 16

Combine real regions and undefined points for final function domain

7 \leq x < 16 or x > 16

\frac{2 x - 14}{x ^{2} - 14 x}

f (x) = lo g_{2} ((\frac{2}{3 x}) - 4)

(x - 7) (x - 9)

f (x) = \frac{5 x ^{2}}{5 x - 5}

\frac{19 x}{x - 3}

What is the domain of f(x)=(sqrt(x-7))/(sqrt(x-7)-3) ?
The domain of f(x)=(sqrt(x-7))/(sqrt(x-7)-3) is 7<= x<16\lor x>16