What is the domain of f(x)=ln((1-x^2)/(3x^2-5x+2)) ?

The domain of f(x)=ln((1-x^2)/(3x^2-5x+2)) is -1<x< 2/3

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domain of f(x)=ln((1-x^2)/(3x^2-5x+2))

domain

f (x) = ln (\frac{1 - x ^{2}}{3 x ^{2} - 5 x + 2})

- 1 < x < \frac{2}{3}

Interval Notation

(- 1, \frac{2}{3})

Solution steps

Find positive values for logs:

- 1 < x < \frac{2}{3}

Find undefined (singularity) points:

x = 1, x = \frac{2}{3}

Combine real regions and undefined points for final function domain

- 1 < x < \frac{2}{3}

x^{3} - 6 x^{2} + 11 x - 6

f (x) = (0.5)^{x}

f (x) = \frac{10}{x} + \frac{x ^{2} - 4}{x - 2}

y = \frac{2 x - 7}{x - 3}

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What is the domain of f(x)=ln((1-x^2)/(3x^2-5x+2)) ?
The domain of f(x)=ln((1-x^2)/(3x^2-5x+2)) is -1<x< 2/3