What is the domain of x/(sqrt(x^2+2)) ?

The domain of x/(sqrt(x^2+2)) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of x/(sqrt(x^2+2))

domain

\frac{x}{x ^{2} + 2}

- \infty < x < \infty

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{6 x}{( x - 5 ) ( x - 9 )}

f (x) = - 2 (x + 4)^{2} - 5

y = x - 1

f (x) = (\frac{( 2 x )}{x ^{2} - 3 x + 2})

y = \frac{1}{x} + 4

What is the domain of x/(sqrt(x^2+2)) ?
The domain of x/(sqrt(x^2+2)) is -infinity <x<infinity