What is the domain of (6x+1)/(1+3x) ?

The domain of (6x+1)/(1+3x) is x -1/3

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domain of (6x+1)/(1+3x)

domain

\frac{6 x + 1}{1 + 3 x}

x < - \frac{1}{3} or x > - \frac{1}{3}

Interval Notation

(- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{3}

The function domain

x < - \frac{1}{3} or x > - \frac{1}{3}

f (x) = \frac{( 1 - x )}{( 2 x - 3 )}

y = \frac{x - 2}{x + 2}

\frac{∣ x - 2 ∣ - 1}{[ x + 3 ] + 2}

y = \frac{x + 6}{15 - x ^{2} - 64}

(x + 3) 2 - 2

What is the domain of (6x+1)/(1+3x) ?
The domain of (6x+1)/(1+3x) is x<-1/3 \lor x>-1/3