What is the domain of f(x)=sqrt(x^2-8x+15) ?

The domain of f(x)=sqrt(x^2-8x+15) is x = 5

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domain of f(x)=sqrt(x^2-8x+15)

domain

f (x) = x^{2} - 8 x + 15

x \leq 3 or x \geq 5

Interval Notation

(- \infty, 3] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 3 or x \geq 5

The function domain

x \leq 3 or x \geq 5

f (x) = \frac{1 + x ^{2}}{x ^{2} - x ^{4}}

f (x) = - e^{- x} + 6

f (x) = - e^{- x} + 8

f (x) = lo g_{10} (x^{2} - 25)

f (x) = \frac{x + 5}{5}

What is the domain of f(x)=sqrt(x^2-8x+15) ?
The domain of f(x)=sqrt(x^2-8x+15) is x<= 3\lor x>= 5