What is the domain of f(x)=sqrt(x^2-8x+16) ?

The domain of f(x)=sqrt(x^2-8x+16) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2-8x+16)

domain

f (x) = x^{2} - 8 x + 16

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 2^{- x} - 7

4 (x - 4) - 3

- \frac{2 x}{x - 3}

9 - x^{2} \cdot (x^{2} + 4) \cdot 2 x - 4

g (x) = \frac{x + 3}{x ^{2} - 25}

What is the domain of f(x)=sqrt(x^2-8x+16) ?
The domain of f(x)=sqrt(x^2-8x+16) is -infinity <x<infinity