What is the domain of 1^{sin(x)} ?

The domain of 1^{sin(x)} is -infinity <x<infinity

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domain of 1^{sin(x)}

domain

1^{s i n (x)}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{2 x ^{3}}{x ^{2} + 1}

x^{2} - 6 x + 14

- \frac{x}{4 - x ^{2}}

f (x) = - 2^{2} + 3 x - 2

y = x - 9 + 7

What is the domain of 1^{sin(x)} ?
The domain of 1^{sin(x)} is -infinity <x<infinity