What is the domain of 1/((\frac{1){x^2})^2} ?

The domain of 1/((\frac{1){x^2})^2} is x 0

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domain of 1/((\frac{1){x^2})^2}

domain

\frac{1}{( \frac{1}{x ^{2}} ) ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{cos ( x )}{1 + tan ( x )}

f (x) = \frac{x - 4}{x ^{2} + 3 x - 40}

f (x) = \frac{2 x + 1}{x + 1}

f (x) = ln (5 t + 10)

f (x) = 3 \frac{y}{( ( y - 6 ) )}

What is the domain of 1/((\frac{1){x^2})^2} ?
The domain of 1/((\frac{1){x^2})^2} is x<0\lor x>0