What is the domain of y=(x-7)/(x^2-12x+35) ?

The domain of y=(x-7)/(x^2-12x+35) is x 7

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domain of y=(x-7)/(x^2-12x+35)

domain

y = \frac{x - 7}{x ^{2} - 12 x + 35}

x < 5 or 5 < x < 7 or x > 7

Interval Notation

(- \infty, 5) \cup (5, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = 5

The function domain

x < 5 or 5 < x < 7 or x > 7

f (x) = (\frac{2}{5})^{x}

f (x) = ln (x) - 2

\frac{x + 6}{7}

1 - x + 4

f (x) = \frac{x ^{2} - 8 x + 12}{x + 3}

What is the domain of y=(x-7)/(x^2-12x+35) ?
The domain of y=(x-7)/(x^2-12x+35) is x<5\lor 5<x<7\lor x>7