What is the domain of x^2-9,x>= 0 ?

The domain of x^2-9,x>= 0 is x>= 0

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domain of x^2-9,x>= 0

domain

x^{2} - 9, x \geq 0

x \geq 0

Interval Notation

Solution steps

Set the domain to the given interval

x \geq 0

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq 0

\frac{8 x - 9}{9 x + 5}

f (x) = ln (0.5 - y)

\frac{x}{x - 5}

f (x) = - \frac{1}{x ( 4 + ln ( x ) ) ^{2}}

f (x) = \frac{2 x + 1}{x - 5}