What is the domain of f(x)=2+sqrt(x^3-2x^2-x+2) ?

The domain of f(x)=2+sqrt(x^3-2x^2-x+2) is -1 = 2

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domain of f(x)=2+sqrt(x^3-2x^2-x+2)

domain

f (x) = 2 + x^{3} - 2 x^{2} - x + 2

- 1 \leq x \leq 1 or x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1 or x \geq 2

The function domain

- 1 \leq x \leq 1 or x \geq 2

f (x) = \frac{70}{x}

f (x) = ln (0.5 + y)

4 [x + 2]

x^{2} + 64

9 x - x^{3}

What is the domain of f(x)=2+sqrt(x^3-2x^2-x+2) ?
The domain of f(x)=2+sqrt(x^3-2x^2-x+2) is -1<= x<= 1\lor x>= 2