What is the domain of (x^2-5x+6)/(sqrt(x^4)-1) ?

The domain of (x^2-5x+6)/(sqrt(x^4)-1) is x 1

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domain of (x^2-5x+6)/(sqrt(x^4)-1)

domain

\frac{x ^{2} - 5 x + 6}{x ^{4} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = cos (1 - 3 x)

e^{x^{2} - 2 x}

f (x) = lo g_{10} (x^{2} + 5 x + 6)

f (x) = ln (7 x - 8)

- 7 x^{2}

What is the domain of (x^2-5x+6)/(sqrt(x^4)-1) ?
The domain of (x^2-5x+6)/(sqrt(x^4)-1) is x<-1\lor-1<x<1\lor x>1