What is the domain of (sqrt(2x-9))/(2x+9) ?

The domain of (sqrt(2x-9))/(2x+9) is x>= 9/2

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domain of (sqrt(2x-9))/(2x+9)

domain

\frac{2 x - 9}{2 x + 9}

x \geq \frac{9}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{9}{2}

Find undefined (singularity) points:

x = - \frac{9}{2}

Combine real regions and undefined points for final function domain

x \geq \frac{9}{2}

\frac{5 x + 8}{6 x - 8}

+ 4 x - 16

f (x) = \frac{y - 10}{y ( y + 2 )}

\frac{4 x}{x ^{2} + 4}

f (x) = \frac{( x ^{2} )}{x ^{4} + 5}

What is the domain of (sqrt(2x-9))/(2x+9) ?
The domain of (sqrt(2x-9))/(2x+9) is x>= 9/2