What is the domain of f(x,y)=x+ln(x^2-1) ?

The domain of f(x,y)=x+ln(x^2-1) is x 1

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domain of f(x,y)=x+ln(x^2-1)

domain

f (x, y) = x + ln (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

y = x + 1 - 2

f (x) = 2 - x - 36 - x^{2}

f (x) = 3 4 x + 8

f (x) = 3 x^{3} + 2

\frac{x - 5}{\frac{x - 5}{x - 9}}

What is the domain of f(x,y)=x+ln(x^2-1) ?
The domain of f(x,y)=x+ln(x^2-1) is x<-1\lor x>1