What is the domain of f(x)=sqrt(4-2x)+5 ?

The domain of f(x)=sqrt(4-2x)+5 is x<= 2

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domain of f(x)=sqrt(4-2x)+5

domain

f (x) = 4 - 2 x + 5

x \leq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

y = 2 x + \frac{5}{2}

\frac{1}{x ^{2} - 16}

f (x) = (x - 4) 2 + 5

f (t) = - t

x^{4} + x

What is the domain of f(x)=sqrt(4-2x)+5 ?
The domain of f(x)=sqrt(4-2x)+5 is x<= 2