What is the domain of f(x)=sqrt(2x-1)-1/x ?

The domain of f(x)=sqrt(2x-1)-1/x is x>= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(2x-1)-1/x

domain

f (x) = 2 x - 1 - \frac{1}{x}

x \geq \frac{1}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \geq \frac{1}{2}

f (x) = 5 - 2 x - 1

f (x) = \frac{x - 4}{8 - x - 2}

f (x) = \frac{2 x}{3 x + 1}

f (x) = ∣ x + 5 ∣

f (x) = \frac{x + 5}{x ^{2} - x - 6}

What is the domain of f(x)=sqrt(2x-1)-1/x ?
The domain of f(x)=sqrt(2x-1)-1/x is x>= 1/2