What is the domain of f(x)=\sqrt[3]{x-1}+sqrt(2x-4) ?

The domain of f(x)=\sqrt[3]{x-1}+sqrt(2x-4) is x>= 2

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domain of f(x)=\sqrt[3]{x-1}+sqrt(2x-4)

domain

f (x) = 3 x - 1 + 2 x - 4

x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = 3^{2 - x} + 1

f (x) = \frac{x - 5}{x ^{2} + 1}

f (x) = 3 5 x + 1

\frac{x - 6}{2 ( x - 3 ) x - 3}

\frac{1}{6} x^{3} - 4

What is the domain of f(x)=\sqrt[3]{x-1}+sqrt(2x-4) ?
The domain of f(x)=\sqrt[3]{x-1}+sqrt(2x-4) is x>= 2