What is the domain of y=(sqrt(9-x^2))/(x^2-x) ?

The domain of y=(sqrt(9-x^2))/(x^2-x) is -3<= x<0\lor 0<x<1\lor 1<x<= 3

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domain of y=(sqrt(9-x^2))/(x^2-x)

domain

y = \frac{9 - x ^{2}}{x ^{2} - x}

- 3 \leq x < 0 or 0 < x < 1 or 1 < x \leq 3

Interval Notation

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 1, x = 0

Combine real regions and undefined points for final function domain

- 3 \leq x < 0 or 0 < x < 1 or 1 < x \leq 3

\frac{3}{x + 4}

\frac{2}{( y + 2 ) ( y - 1 )}

f (x) = \frac{x - 2}{x - 4}

\frac{3 2 x - 4}{2 x - 4 - 2}

f (x,) = ln (x)

What is the domain of y=(sqrt(9-x^2))/(x^2-x) ?
The domain of y=(sqrt(9-x^2))/(x^2-x) is -3<= x<0\lor 0<x<1\lor 1<x<= 3