What is the domain of h(x)=sqrt((x^2-4)/2) ?

The domain of h(x)=sqrt((x^2-4)/2) is x = 2

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domain of h(x)=sqrt((x^2-4)/2)

domain

h (x) = \frac{x ^{2} - 4}{2}

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = \frac{4 x}{x ^{2} + 1}

x^{4} - 8 x^{2} + 17

f (x) = 5 - 2 x + 2

lo g_{10} (∣ x - 1 ∣)

(x) (e^{\frac{5 - x}{4}})

What is the domain of h(x)=sqrt((x^2-4)/2) ?
The domain of h(x)=sqrt((x^2-4)/2) is x<=-2\lor x>= 2