What is the domain of f(x)=sqrt(-x^2-4x+4) ?

The domain of f(x)=sqrt(-x^2-4x+4) is -2sqrt(2)-2<= x<= 2sqrt(2)-2

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domain of f(x)=sqrt(-x^2-4x+4)

domain

f (x) = - x^{2} - 4 x + 4

- 22 - 2 \leq x \leq 22 - 2

Interval Notation

[- 22 - 2, 22 - 2]

Solution steps

Find non-negative values for radicals:

- 22 - 2 \leq x \leq 22 - 2

The function domain

- 22 - 2 \leq x \leq 22 - 2

f (x) = \frac{x ^{2}}{x ^{2} - 25}

f (x) = \frac{10 - x}{2 x}

f (x) = - 3 + \frac{1}{2}

2 3 x - 3

f (x) = x - 3 - x + 4

What is the domain of f(x)=sqrt(-x^2-4x+4) ?
The domain of f(x)=sqrt(-x^2-4x+4) is -2sqrt(2)-2<= x<= 2sqrt(2)-2