What is the domain of (x^3-8)/(x^2-16) ?

The domain of (x^3-8)/(x^2-16) is x 4

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domain of (x^3-8)/(x^2-16)

domain

\frac{x ^{3} - 8}{x ^{2} - 16}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

7 x - 7

6 x^{2} + 7 x + 26 x^{2} - 5 x - 6

g (s) = \frac{1}{s ^{2} - 4 - 2}

f (x) = x^{\frac{3}{4}}

f (x) = \frac{5 x - 2}{x - 4}

What is the domain of (x^3-8)/(x^2-16) ?
The domain of (x^3-8)/(x^2-16) is x<-4\lor-4<x<4\lor x>4