What is the domain of x/(x^2+2x-3) ?

The domain of x/(x^2+2x-3) is x 1

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domain of x/(x^2+2x-3)

domain

\frac{x}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = \frac{4 x ^{2} - 8}{x ^{2} + 4}

y = \frac{x - 1}{x - 4}

f (x) = - - 2 x + 5

\frac{x + 7}{x + 11}

f (x) = \frac{x + 6}{x ^{2} + 2 x - 24}

What is the domain of x/(x^2+2x-3) ?
The domain of x/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1