What is the domain of 2-log_{1/3}(x-1) ?

The domain of 2-log_{1/3}(x-1) is x>1

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domain of 2-log_{1/3}(x-1)

domain

2 - lo g_{\frac{1}{3}} (x - 1)

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

- x^{2} ln (x)

\frac{2 x + 4}{x - 1}

f (x) = 3 + lo g_{3} (x + 2)

f (x) = 2 + 9 - x^{2}

\frac{3}{x + 2} + 1