What is the domain of f(x)=(1+1/x)^2 ?

The domain of f(x)=(1+1/x)^2 is x 0

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domain of f(x)=(1+1/x)^2

domain

f (x) = (1 + \frac{1}{x})^{2}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = x + \frac{256}{x ^{2}}

f (x) = - 9 - x

f (x) = \frac{2 x - 9}{2 x + 9}

lo g_{4} (x + 1) - 2

f (x) = \frac{x ^{2} - 4}{2}

What is the domain of f(x)=(1+1/x)^2 ?
The domain of f(x)=(1+1/x)^2 is x<0\lor x>0