What is the domain of f(x)= x/(x^2-6x+5)+(x-3)/(2x) ?

The domain of f(x)= x/(x^2-6x+5)+(x-3)/(2x) is x 5

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domain of f(x)= x/(x^2-6x+5)+(x-3)/(2x)

domain

f (x) = \frac{x}{x ^{2} - 6 x + 5} + \frac{x - 3}{2 x}

x < 0 or 0 < x < 1 or 1 < x < 5 or x > 5

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or 1 < x < 5 or x > 5

y = \frac{2 x ^{2} - 5 x + 3}{4 x - 4}

f (x) = lo g_{5} (1 - 3 x)

f (x) = \frac{30}{12 x - 26}

f (x) = - x^{2} - 4 x - 9

f (x) = \frac{x - 1}{2 x + 2}

What is the domain of f(x)= x/(x^2-6x+5)+(x-3)/(2x) ?
The domain of f(x)= x/(x^2-6x+5)+(x-3)/(2x) is x<0\lor 0<x<1\lor 1<x<5\lor x>5