What is the domain of f(x)=-4+sqrt(3x-12) ?

The domain of f(x)=-4+sqrt(3x-12) is x>= 4

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domain of f(x)=-4+sqrt(3x-12)

domain

f (x) = - 4 + 3 x - 12

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

\frac{1}{2} x^{2} e^{x + 1}

f (x) = \frac{3}{4 - x ^{2}}

f (y) = y - 4

\frac{2 x}{4 - 7 x}

What is the domain of f(x)=-4+sqrt(3x-12) ?
The domain of f(x)=-4+sqrt(3x-12) is x>= 4