What is the domain of f(x)=y^2=16-x^2 ?

The domain of f(x)=y^2=16-x^2 is -infinity <x<infinity

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domain of f(x)=y^2=16-x^2

domain

f (x) = y^{2} = 16 - x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x \cdot ln (x^{2})

f (x) = 3 cot (2 x)

f (x) = \frac{8}{x + 1}

f (x) = \frac{1}{2} x + π

f (x) = \frac{8}{x + 2}

What is the domain of f(x)=y^2=16-x^2 ?
The domain of f(x)=y^2=16-x^2 is -infinity <x<infinity