What is the domain of 1/(sqrt(-x^2+6x)) ?

The domain of 1/(sqrt(-x^2+6x)) is 0<x<6

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domain of 1/(sqrt(-x^2+6x))

domain

\frac{1}{- x ^{2} + 6 x}

0 < x < 6

Interval Notation

(0, 6)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 6

Find undefined (singularity) points:

x = 0, x = 6

Combine real regions and undefined points for final function domain

0 < x < 6

f (x) = \frac{- 4 x ^{2}}{( x - 3 ) ( x + 1 )}

f (x) = \frac{3 x}{x - 8}

f (x) = - 4 x + 1 = - 5

y = 1 - \frac{x ^{2}}{9}

\frac{1}{3} (x - 2.1)^{2} + 7.9

What is the domain of 1/(sqrt(-x^2+6x)) ?
The domain of 1/(sqrt(-x^2+6x)) is 0<x<6