What is the domain of x/(\sqrt[4]{x^2-5x)} ?

The domain of x/(\sqrt[4]{x^2-5x)} is x 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of x/(\sqrt[4]{x^2-5x)}

domain

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

Find undefined (singularity) points:

x = 5, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 5

f (t) = \frac{1}{t}

f (x) = \frac{2}{2 + 2 ^{\frac{1}{x}}}

f (x) = \frac{x - 2}{x ^{2} + 2 x - 8}

f (x) = 2 x^{(3)} + 3 x^{(2)} - 12 x - 7

What is the domain of x/(\sqrt[4]{x^2-5x)} ?
The domain of x/(\sqrt[4]{x^2-5x)} is x<0\lor x>5