What is the domain of f(x)=sqrt((x+8)/2-5) ?

The domain of f(x)=sqrt((x+8)/2-5) is x>= 2

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domain of f(x)=sqrt((x+8)/2-5)

domain

f (x) = \frac{x + 8}{2} - 5

x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = - 3 x^{4} + 7 x^{2} - 5

\frac{x - 2}{x + 2}

\frac{3 x - 5}{x - 2}

x - 23 + \frac{253}{x + 11}

f (x) = lo g_{2} (3 x - 6) + \frac{1}{x - 5}

What is the domain of f(x)=sqrt((x+8)/2-5) ?
The domain of f(x)=sqrt((x+8)/2-5) is x>= 2