What is the domain of 1/(\sqrt[4]{9-x^2)} ?

The domain of 1/(\sqrt[4]{9-x^2)} is -3<x<3

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domain of 1/(\sqrt[4]{9-x^2)}

domain

\frac{1}{4 9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

f (x) = \frac{1}{x ^{2} + x - 2}

f (x) = 200 - \frac{x}{30}

f (x) = - \frac{2}{x ^{2} + 2 x - 35}

f (x) = 2 x + 3, x \geq - 4

x e^{s i n (x)}

What is the domain of 1/(\sqrt[4]{9-x^2)} ?
The domain of 1/(\sqrt[4]{9-x^2)} is -3<x<3