What is the domain of f(t)=\sqrt[6]{t-2/(3+5t)} ?

The domain of f(t)=\sqrt[6]{t-2/(3+5t)} is -1 = 2/5

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domain of f(t)=\sqrt[6]{t-2/(3+5t)}

domain

f (t) = 6 t - \frac{2}{3 + 5 t}

- 1 \leq t < - \frac{3}{5} or t \geq \frac{2}{5}

Interval Notation

Solution steps

Find non-negative values for radicals:

- 1 \leq t < - \frac{3}{5} or t \geq \frac{2}{5}

Find undefined (singularity) points:

t = - \frac{3}{5}

Combine real regions and undefined points for final function domain

- 1 \leq t < - \frac{3}{5} or t \geq \frac{2}{5}

lo g_{10} (x - 6)

y

f (x) = 9 3 x + 2

\frac{x + 1}{x - 1}

- 0.025 X + 0.89

What is the domain of f(t)=\sqrt[6]{t-2/(3+5t)} ?
The domain of f(t)=\sqrt[6]{t-2/(3+5t)} is -1<= t<-3/5 \lor t>= 2/5