What is the domain of (x^3-1)/(x^2-9) ?

The domain of (x^3-1)/(x^2-9) is x 3

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domain of (x^3-1)/(x^2-9)

domain

\frac{x ^{3} - 1}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

3 x - x^{2}

f (x) = \frac{9 - 6 x}{x ^{3} - 9 x ^{2} - 8 x}

\frac{sin ( 2 x )}{1 + sin ( 2 x )}

y = \frac{1 - e ^{x^{2}}}{1 - e ^{1 - x^{2}}}

f (x) = (3 x - 3)

What is the domain of (x^3-1)/(x^2-9) ?
The domain of (x^3-1)/(x^2-9) is x<-3\lor-3<x<3\lor x>3