What is the domain of f(x)=(x-6)/(x^2+x-42) ?

The domain of f(x)=(x-6)/(x^2+x-42) is x 6

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domain of f(x)=(x-6)/(x^2+x-42)

domain

f (x) = \frac{x - 6}{x ^{2} + x - 42}

x < - 7 or - 7 < x < 6 or x > 6

Interval Notation

(- \infty, - 7) \cup (- 7, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 7

The function domain

x < - 7 or - 7 < x < 6 or x > 6

f (x) = \frac{2 x - 3}{x}

f (x) = \frac{7 x + 6}{x - 1}

f (x) = \frac{lo g _{10} ( x )}{x - 2}

f (x) = ln \frac{x + 1}{x - 1}

f (s) = \frac{4 - s ^{2}}{2 s ^{2} - 7 s - 4}

What is the domain of f(x)=(x-6)/(x^2+x-42) ?
The domain of f(x)=(x-6)/(x^2+x-42) is x<-7\lor-7<x<6\lor x>6