What is the domain of (x^2-x-6)/(x^2-4x+3) ?

The domain of (x^2-x-6)/(x^2-4x+3) is x 3

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domain of (x^2-x-6)/(x^2-4x+3)

domain

\frac{x ^{2} - x - 6}{x ^{2} - 4 x + 3}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

g (x) = 3 x^{2} - x + 5

f (x) = 3 sin (\frac{1}{3} x) + 1

9 x + 1

f (x) = x^{2} ln (8 - 3 x^{2})

2 x^{3} - 9 x^{2} + 12 x - 3

What is the domain of (x^2-x-6)/(x^2-4x+3) ?
The domain of (x^2-x-6)/(x^2-4x+3) is x<1\lor 1<x<3\lor x>3