What is the domain of y=(2x^2)/(x^2-1) ?

The domain of y=(2x^2)/(x^2-1) is x 1

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domain of y=(2x^2)/(x^2-1)

domain

y = \frac{2 x ^{2}}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{x + 2}{2 x - 12}

f (x) = 5 x^{2} - 30 x + 49

f (x) = 2 x^{2} + x - 6

x^{5} - 3 x^{3} + 5 x

\frac{x + 4}{x ^{2} + 3 x - 4}

What is the domain of y=(2x^2)/(x^2-1) ?
The domain of y=(2x^2)/(x^2-1) is x<-1\lor-1<x<1\lor x>1