What is the domain of f(x)= 1/((x^2-(|x|))) ?

The domain of f(x)= 1/((x^2-(|x|))) is x 1

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domain of f(x)= 1/((x^2-(|x|)))

domain

f (x) = \frac{1}{( x ^{2} - ( ∣ x ∣ ) )}

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 0, x = 1

The function domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

f (x) = 4, 0 \leq y \leq 70

f (x) = lo g_{5} (3 x + 1)

f (x) = \frac{( 6 - 6 x )}{( 2 + 6 x )}

f (x) = 3 x + 11

f (x) = 7 - x - x - 2

What is the domain of f(x)= 1/((x^2-(|x|))) ?
The domain of f(x)= 1/((x^2-(|x|))) is x<-1\lor-1<x<0\lor 0<x<1\lor x>1