What is the domain of (2x+3)/(3x^2+7x-6) ?

The domain of (2x+3)/(3x^2+7x-6) is x 2/3

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domain of (2x+3)/(3x^2+7x-6)

domain

\frac{2 x + 3}{3 x ^{2} + 7 x - 6}

x < - 3 or - 3 < x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, - 3) \cup (- 3, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}, x = - 3

The function domain

x < - 3 or - 3 < x < \frac{2}{3} or x > \frac{2}{3}

f (x) = \frac{2 x}{7 x - 20}

f (x) = 2^{(x + 1)}

f (x) = \frac{3 x + 1}{5 x - 20}

f (x) = 3 \frac{( 3 x + 2 )}{x + 1}

\frac{( x ^{2} - x - 6 )}{x - 4}

What is the domain of (2x+3)/(3x^2+7x-6) ?
The domain of (2x+3)/(3x^2+7x-6) is x<-3\lor-3<x< 2/3 \lor x> 2/3