What is the domain of f(x)=-(x-4)(x+2)(x-1) ?

The domain of f(x)=-(x-4)(x+2)(x-1) is -infinity <x<infinity

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domain of f(x)=-(x-4)(x+2)(x-1)

domain

f (x) = - (x - 4) (x + 2) (x - 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

3 + x + 2

f (x) = 5 x - 2

\frac{x - 5}{x + 1}

h (x) = 8

g (x) = 3^{x} - 2

What is the domain of f(x)=-(x-4)(x+2)(x-1) ?
The domain of f(x)=-(x-4)(x+2)(x-1) is -infinity <x<infinity