What is the domain of f(x)=\sqrt[4]{2x+8} ?

The domain of f(x)=\sqrt[4]{2x+8} is x>=-4

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domain of f(x)=\sqrt[4]{2x+8}

domain

f (x) = 4 2 x + 8

x \geq - 4

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = ln (- 4.4)

ln (x^{4} ln^{2} (ln (x)))

f (x) = \frac{2}{x ^{2} + 3}

f (x) = \frac{4 - x ^{2}}{x}

e^{5 x}

What is the domain of f(x)=\sqrt[4]{2x+8} ?
The domain of f(x)=\sqrt[4]{2x+8} is x>=-4