What is the domain of f(x)=(x+1)/(x^2+3x-40) ?

The domain of f(x)=(x+1)/(x^2+3x-40) is x 5

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domain of f(x)=(x+1)/(x^2+3x-40)

domain

f (x) = \frac{x + 1}{x ^{2} + 3 x - 40}

x < - 8 or - 8 < x < 5 or x > 5

Interval Notation

(- \infty, - 8) \cup (- 8, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 8

The function domain

x < - 8 or - 8 < x < 5 or x > 5

f (x) = 8750 \cdot 0.8 8^{0}

x + 13

f (x) = \frac{x + 6}{3}

\frac{10 x - 25}{4 x + 18}

f (x) = \frac{x}{5 x - 3}

What is the domain of f(x)=(x+1)/(x^2+3x-40) ?
The domain of f(x)=(x+1)/(x^2+3x-40) is x<-8\lor-8<x<5\lor x>5