What is the domain of f(x)=sqrt((2x^2)) ?

The domain of f(x)=sqrt((2x^2)) is -infinity <x<infinity

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domain of f(x)=sqrt((2x^2))

domain

f (x) = (2 x^{2})

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x^{2} + 2 x - x

g (x) = \frac{∣ x ∣}{x ^{2}}

\frac{( 3 x + 5 )}{( 2 x - 7 )}

f (x) = - 8 x + 5

y = \frac{5 - 7 x}{2 x + 3}

What is the domain of f(x)=sqrt((2x^2)) ?
The domain of f(x)=sqrt((2x^2)) is -infinity <x<infinity