What is the domain of f(x)=sqrt((x^2-1)/(x^2+1)) ?

The domain of f(x)=sqrt((x^2-1)/(x^2+1)) is x = 1

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domain of f(x)=sqrt((x^2-1)/(x^2+1))

domain

f (x) = \frac{x ^{2} - 1}{x ^{2} + 1}

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

y = sin (arcsin (x))

\frac{1}{( x - 6 ) ^{2}}

f (x) = \frac{1}{( x + 4 ) x + 6}

f (x) = \frac{x - 7}{x - 5}

f (x) = x + 1 - x

What is the domain of f(x)=sqrt((x^2-1)/(x^2+1)) ?
The domain of f(x)=sqrt((x^2-1)/(x^2+1)) is x<=-1\lor x>= 1